(2^2x)+(2^x+1)=80

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Solution for (2^2x)+(2^x+1)=80 equation:



(2^2x)+(2^x+1)=80
We move all terms to the left:
(2^2x)+(2^x+1)-(80)=0
We get rid of parentheses
2^2x+2^x+1-80=0
We add all the numbers together, and all the variables
2^2x+2^x-79=0
We move all terms containing x to the left, all other terms to the right
2^2x+2^x=79

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